Potencies high potencies - Printable Version

Potencies high potencies - Printable Version

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Potencies high potencies - Kernelpanic - 10-07-2024

When I wanted to try something today, I came across a problem, at least for me.
The results do not match what the MS calculator and online calculators give. I am also confused by the fact that ((5 ^ 4)^4) is not the same as 5^(4*4) for the program, but 5^16 gives a result like ((5 ^ 4)^4). Have I there disregarded some mathematical laws? Huh

Code: (Select All)



'Matheuebung Potenzen hoch Potenzen - 7. Okt. 2024



Option _Explicit



Dim As Integer a, b, c

Dim As _Unsigned Long sum, sum2, sum3



Locate 2, 3

Print "Berechnet ((a ^ b) ^ c)"

Locate 3, 3

Print "======================="

'Beispiel: ((5^4)^4) = 5^16

'MS-Rechner: 152.587.890.625 -- Hier: 2.264.035.265



Locate 5, 3

Input "a: ", a

Locate 6, 3

Input "b: ", b

Locate 7, 3

Input "c: ", c



sum = ((a ^ b) ^ c)

Locate 9, 3

Print Using "Summe 1: ###,##########"; sum



sum2 = a ^ (a * b)

Locate 11, 3

Print Using "Summe 2: ###,##########"; sum2



sum3 = a ^ 16

Locate 13, 3

Print Using "Summe 3: ###,##########"; sum3



End

Math-Solver

RE: Potencies high potencies - bplus - 10-07-2024

(10-07-2024, 09:21 PM)Kernelpanic Wrote: When I wanted to try something today, I came across a problem, at least for me.
The results do not match what the MS calculator and online calculators give. I am also confused by the fact that ((5 ^ 4)^4) is not the same as 5^(4*4) for the program, but 5^16 gives a result like ((5 ^ 4)^4). Have I there disregarded some mathematical laws?

Code: (Select All)
'Matheuebung Potenzen hoch Potenzen - 7. Okt. 2024



Option _Explicit



Dim As Integer a, b, c

Dim As _Unsigned Long sum, sum2, sum3



Locate 2, 3

Print "Berechnet ((a ^ b) ^ c)"

Locate 3, 3

Print "======================="

'Beispiel: ((5^4)^4) = 5^16

'MS-Rechner: 152.587.890.625 -- Hier: 2.264.035.265



Locate 5, 3

Input "a: ", a

Locate 6, 3

Input "b: ", b

Locate 7, 3

Input "c: ", c



sum = ((a ^ b) ^ c)

Locate 9, 3

Print Using "Summe 1: ###,##########"; sum



sum2 = a ^ (a * b)

Locate 11, 3

Print Using "Summe 2: ###,##########"; sum2



sum3 = a ^ 16

Locate 13, 3

Print Using "Summe 3: ###,##########"; sum3



End
Math-Solver

4^4 is not 16

yeah so how you group them makes a difference
5^4 then ^4
is far less than
5 ^(4^4)

RE: Potencies high potencies - Kernelpanic - 10-07-2024

4^4 = 256, that's clear. But from what I've read, ((5^4)^4) should be equal to 5^(4*4). That's how the MS calculator shows it.
So that should be mathematically correct.

RE: Potencies high potencies - LEM - 10-07-2024

(10-07-2024, 10:20 PM)Kernelpanic Wrote: 4^4 = 256, that's clear. But from what I've read, ((5^4)^4) should be equal to 5^(4*4). That's how the MS calculator shows it.
So that should be mathematically correct.

You are correct that ((5^4)^4) is the same as 5^16. I think your issue is dimensioning the "sum" variables as long (or unsigned long). The result of 5^16 is much larger than can be represented by a long, I think. Try without dimensioning as unsigned long.

RE: Potencies high potencies - Kernelpanic - 10-08-2024

Quote:@LEM - I think your issue is dimensioning the "sum" variables as long (or unsigned long). The result of 5^16 is much larger than can be represented by a long, I think. Try without dimensioning as unsigned long.

Thanks, that was it! And a typo in sum 2 was the reason for the wrong result. Now it works.

Code: (Select All)



'Matheuebung Potenzen hoch Potenzen - 7./8. Okt. 2024



Option _Explicit



Dim As Integer a, b, c

Dim As _Integer64 sum, sum2, sum3



Locate 2, 3

Print "Berechnet ((a ^ b) ^ c)"

Locate 3, 3

Print "======================="

'Beispiel: ((5^4)^4) = 5^16

'MS-Rechner: 152.587.890.625 -- Hier: 2.264.035.265



Locate 5, 3

Input "a: ", a

Locate 6, 3

Input "b: ", b

Locate 7, 3

Input "c: ", c



sum = ((a ^ b) ^ c)

Locate 9, 3

Print Using "Summe 1: ###,############"; sum



sum2 = a ^ (c * b)

Locate 11, 3

Print Using "Summe 2: ###,############"; sum2



sum3 = a ^ 16

Locate 13, 3

Print Using "Summe 3: ###,############"; sum3



End