Date functions

[Kernelpanic]

I think all are good, just depends on need and style 

Yes, thanks! Today it's just a hobby for me to distract myself.
I loved programming and would like to do it as much as I used to, but times have changed.

C'est la vie, as the Frenchman says!

[dano]

For date difference calculations why not convert to Julian and get the difference?

Code: (Select All)

Start:

Input "Date1: ", d1$

If d1$ = "" Then System

Input "Date2: ", d2$

Print "Difference in days: "; Julian#(d2$) - Julian#(d1$)

Print: Print: Print

GoTo Start







Function Julian# (from$)

    'Gives # of days since Monday, January 1, 4713 BC

    'accepts xx-xx-xxxx OR xx/xx/xxxx OR xx-xx-xx OR xx/xx/xx



    'from$ must be either 8 or 10 characters

    If Len(from$) <> 8 And Len(from$) <> 10 Then Julian# = 0: Exit Function



    'must be xx-xx or xx/xx format

    If Mid$(from$, 3, 1) <> "-" And Mid$(from$, 3, 1) <> "/" Then Julian# = 0: Exit Function

    If Mid$(from$, 6, 1) <> "-" And Mid$(from$, 6, 1) <> "/" Then Julian# = 0: Exit Function



    Month% = Val(Mid$(from$, 1, 2))

    Day% = Val(Mid$(from$, 4, 2))

    If Len(from$) = 10 Then

        Year% = Val(Right$(from$, 4))

    ElseIf Len(from$) = 8 Then

        Year% = Val("20" + Right$(from$, 2))

    End If



    Select Case Month%

        Case Is >= 3

            Month% = Month% - 3

        Case Is <= 2

            Month% = Month% + 9

            Year% = Year% - 1

    End Select



    A# = 146097# * Fix(Fix(Year% / 100) / 4)

    B# = Fix(1461# * (Year% Mod 100) / 4)

    C# = Fix((153# * Month% + 2) / 5) + Day% + 1721119



    Julian# = A# + B# + C#

End Function