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Scrabble Dictionary
#11
(11-24-2022, 04:12 AM)PhilOfPerth Wrote: I don't really see the point of Random Access for the words; probably I'm missing something again.   Confused
Maybe a quicksort routine would help speed things up though.
Anyway, I'm half-way through creating matching Meanings files, so I'll stay with that for now.

With Random Access I can use Binary Search instead of running through every word in file to find a word. Every time I test a word I reduce the number of words to search by one half.

You split up the words into letter files to reduce search times.
b = b + ...
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#12
From my opening post, it uses a binary search for our word array: 
Code: (Select All)
Function BinaryStringSearch (search$, Array() As String)
    'These routines work with actual indexes, so we can search from Array(-10 to 10), if we want to.
    'When the search string is found, it'll return a value = to the index proper.
    'When it's not found, it'll return a value LESS THAN the LBOUND limit of the array,
    'And the point where the string WOULD'VE appeared, if it existed, is after the shared variable LastIndex

    BinaryStringSearch = BinaryStringSearchSome(search$, Array(), LBound(Array), UBound(Array))
End Function

Function BinaryStringSearchSome (search$, Array() As String, StartIndex As Long, EndIndex As Long)
    'These routines work with actual indexes, so we can search from Array(-10 to 10), if we want to.
    'When the search string is found, it'll return a value = to the index proper.
    'When it's not found, it'll return a value LESS THAN the LBOUND limit of the array,
    'And the point where the string WOULD'VE appeared, if it existed, is after the shared variable LastIndex

    min = StartIndex
    max = EndIndex

    Do
        gap = (max + min) \ 2
        compare = _StrCmp(search$, Array(gap))
        If compare > 0 Then
            min = gap + 1
        ElseIf compare < 0 Then
            max = gap - 1
        Else
            BinaryStringSearchSome = gap
            Exit Function
        End If
        If max - min < 1 Then
            If search$ = Array(min) Then
                BinaryStringSearchSome = min
            Else
                BinaryStringSearchSome = LBound(Array) - 1
                If search$ < Array(min) Then
                    LastIndex = min - 1
                Else
                    LastIndex = min
                End If
            End If
            found = -1
        End If
    Loop Until found
End Function
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#13
Here's mine for an opened RA file of which I already know Word count, 32 is maximum word length (guessed):
Code: (Select All)
Function findW& (wd$)
    Dim As Long lo, hi, m
    Dim wrd As String * 32
    lo = 1: hi = 279422
    While lo <= hi
        m = (hi + lo) / 2
        Get #1, m, wrd
        w$ = _Trim$(wrd)
        If w$ = wd$ Then
            findW& = m: Exit Function
        ElseIf w$ < wd$ Then
            lo = m + 1
        ElseIf w$ > wd$ Then
            hi = m - 1
        End If
    Wend
End Function
b = b + ...
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#14
(11-24-2022, 04:29 AM)bplus Wrote:
(11-24-2022, 04:12 AM)PhilOfPerth Wrote: I don't really see the point of Random Access for the words; probably I'm missing something again.   Confused
Maybe a quicksort routine would help speed things up though.
Anyway, I'm half-way through creating matching Meanings files, so I'll stay with that for now.

With Random Access I can use Binary Search instead of running through every word in file to find a word. Every time I test a word I reduce the number of words to search by one half.

You split up the words into letter files to reduce search times.
I just ran a test for worst-case read and compare for the largest wordlists file (S, with 31947 items) and it took 1.04 seconds for the test, so I don't think I'll worry about changing to RA. I will look at RA though, for my own "education".
Of all the places on Earth, and all the planets in the Universe, I'd rather live here (Perth, W.A.) Big Grin
Please visit my Website at: http://oldendayskids.blogspot.com/
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#15
Worst case for me with RA, I have to test 19 words!
Code: (Select All)
words = 279422
While words > 1
    words = words / 2
    count = count + 1
Wend
Print count
But I am sure I encounter my worst case more often.
b = b + ...
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