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Hello
How to replace MOD to get correct results.
I have been using the MOD for a long time without problems. The problems started with negative values.
(-1 MOD 5) => (-1)
(-1.4 MOD 5) => (-1)
(1.4 MOD 5) => (1)
(-7. MOD 5) => (-2)
(-7.1 MOD 5) => (-2)
All results are incorrect.
Regards - Chris
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This is another operator that will give the correct results?
Chris
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What do you consider to be correct results?
5 MOD 5 = 0
4 MOD 5 = 4
3 MOD 5 = 3
2 MOD 5 = 2
1 MOD 5 = 1
0 MOD 5 = 0
-1 MOD 5 = 4
-2 MOD 5 = 3
-3 MOD 5 = 2
-4 MOD 5 = 1
-5 MOD 5 = 0
-6 MOD 5 = 4
-7 MOD 5 = 3
^Is that the patten/results you're looking for?
If so, then just do something simple like:
FUNCTION ModAll&& (number as _INTEGER64, number2 AS LONG)
temp&& = number MOD number2
IF temp&& < 0 THEN temp&& = temp&& + number
ModAll = temp&&
END FUNCTION
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That's exactly what I mean.
It cannot be done without the function ?.
Chris
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MOD often require some user adjustments, such as coding a function, to fit specific desired patterns.
As far as a different keyword to get what want, none that I'm aware of.
Pete
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To the creators of QB64. Can we expect in the near future that a new operator to solve this type of computation will be planted into QB64?
Chris
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But Steve's function is good enough, why try to force a BASIC dialect into a "new" implementation of a function that is mathematically sound?