Dang that disables the QB64 code!
i = (r * sq) + c + 1 ' All these are integers already so i is integer already
Does QBJS ignore integer types?
i = (r * sq) + c + 1 ' All these are integers already so i is integer already
Does QBJS ignore integer types?
724 855 599 923 575 468 400 206 147 564 878 823 652 556 bxor cross forever

