Testing 79
79 / 3 = 26 R 1 79 - 26 - 1 = 52
52 / 3 = 17 R 1 52 - 17 - 1 = 34
34 / 3 = 11 R 1 34 - 11 - 1 = 22
22 / 3 = 7 R 1 so 7 more for each friend and donkey gets the 4 Remainders.
26 + 7 = 33 1st
17 + 7 = 24 2nd
11 + 7 = 18 3rd
+4 Donkey
= 79 It works alright I stand corrected
Where did I go wrong?
Aha! i5 mod 3 = 0 was not required!
Well it wouldn't be right to be first AND be correct ;-))
79 / 3 = 26 R 1 79 - 26 - 1 = 52
52 / 3 = 17 R 1 52 - 17 - 1 = 34
34 / 3 = 11 R 1 34 - 11 - 1 = 22
22 / 3 = 7 R 1 so 7 more for each friend and donkey gets the 4 Remainders.
26 + 7 = 33 1st
17 + 7 = 24 2nd
11 + 7 = 18 3rd
+4 Donkey
= 79 It works alright I stand corrected
Where did I go wrong?
Code: (Select All)
For i = 1 To 4000
If i Mod 3 = 1 Then
i2 = i - Int(i / 3) - 1 '1st
If i2 Mod 3 = 1 Then
i3 = i2 - Int(i2 / 3) - 1 '2nd
If i3 Mod 3 = 1 Then
i4 = i3 - Int(i3 / 3) - 1 ' 3rd
If i4 Mod 3 = 1 Then
i5 = i4 - Int(i4 / 3) - 1 '4th
'If i5 Mod 3 = 0 Then
Print i; "="; i2 / 2 + i5 / 2; "+"; i3 / 2 + i5 / 2; "+"; i4 / 2 + i5 / 2; "+"; 4
Exit For
'End If
End If
End If
End If
End If
Next
Aha! i5 mod 3 = 0 was not required!
Well it wouldn't be right to be first AND be correct ;-))
Quote:Friend 1 is a pig.ha! Friend 1 was the earliest bird for the worm laden apples
b = b + ...