_mem

[Jack]

regarding _Mem, run the following snippet

Code: (Select All)

Dim m As _MEM

Dim As Long i

Dim As _Byte ascii

Dim As String * 80 s



m = _Mem(s)



For i = 0 To 79

    ascii = 33 + i

    _MemPut m, m.OFFSET + i, ascii

Next



Print s

it's clear that the memory allocated to the string s is being addressed, so why do I need to free m which behaves as a pointer to s ?