02-26-2026, 05:30 AM
(02-26-2026, 05:09 AM)SMcNeill Wrote: Result = FindWord(dictionary_array() AS STRING, theWord AS STRING)
If the result is 0, it’s not found.
Any other result is the position in the array where the word was located at.
Still not getting it... Gives an error "Name already in use (As) " with whatever I try as theWord :
"THIS";
THIS;
theWord="THIS"...
(told ya I wasn't "most" - I aint smart but I can lift heavy fings)!!!
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