_NEWIMAGE can't accept variables as dimensions?

[bobalooie]

I am working on a project in which I would like to create images using _NEWIMAGE and calculated image dimensions. I have found that an 'Illegal Function Call' error is raised when I try to create an image like this:

DIM AS LONG Pict
DIM AS INTEGER iy
.
.
.
Pict =_NEWIMAGE(64, iy, 32)

Does _NEWIMAGE accept only numeric values for the dimensions? The wiki doesn't specifically say so but all of the examples use numeric dimension values. 

TIA

[ahenry3068]

I am working on a project in which I would like to create images using _NEWIMAGE and calculated image dimensions. I have found that an 'Illegal Function Call' error is raised when I try to create an image like this:

DIM AS LONG Pict
DIM AS INTEGER iy
.
.
.
Pict =_NEWIMAGE(64, iy, 32)

Does _NEWIMAGE accept only numeric values for the dimensions? The wiki doesn't specifically say so but all of the examples use numeric dimension values. 

TIA

  A variable should be acceptable.


   If that is the full code your using then your getting the illegal function call because iu isn't assigned a value (thus is 0)  You can't do a _NEWIMAGE with a 0 dimension !

[bobalooie]

  A variable should be acceptable.


   If that is the full code your using then your getting the illegal function call because iu isn't assigned a value (thus is 0)  You can't do a _NEWIMAGE with a 0 dimension !

The variable's value is calculated before reaching this point in the code. It is a non-zero value.

[ahenry3068]

  A variable should be acceptable.


   If that is the full code your using then your getting the illegal function call because iu isn't assigned a value (thus is 0)  You can't do a _NEWIMAGE with a 0 dimension !

The variable's value is calculated before reaching this point in the code. It is a non-zero value.

   In that case please print out the values just prior to the _newimage.     !     The code you have should work if iy is a valid value !

---

Also make sure the variable is **in scope** you may think your initializing it but really getting the WRONG iy if the one your assigning isn't in the scope of the _newimage

[bobalooie]

  A variable should be acceptable.


   If that is the full code your using then your getting the illegal function call because iu isn't assigned a value (thus is 0)  You can't do a _NEWIMAGE with a 0 dimension !

The variable's value is calculated before reaching this point in the code. It is a non-zero value.

   In that case please print out the values just prior to the _newimage.     !     The code you have should work if iy is a valid value !

---

Also make sure the variable is **in scope** you may think your initializing it but really getting the WRONG iy if the one your assigning isn't in the scope of the _newimage

The action is all within a SUB, including the variable declarations, so everything is in the local scope. I have single-stepped through the code and put the variables on the watchlist. The iy values start at 16 and can be increased but never reduced.

[ahenry3068]

The variable's value is calculated before reaching this point in the code. It is a non-zero value.

   In that case please print out the values just prior to the _newimage.     !     The code you have should work if iy is a valid value !

---

Also make sure the variable is **in scope** you may think your initializing it but really getting the WRONG iy if the one your assigning isn't in the scope of the _newimage

The action is all within a SUB, including the variable declarations, so everything is in the local scope. I have single-stepped through the code and put the variables on the watchlist. The iy values start at 16 and can be increased but never reduced.

   I know I use variables with _NEWIMAGE,  But I believe in double checking.  

This code DOES NOTHING REALLY,   But it compiles and runs without an error ! 

Code: (Select All)

Dim IX As Integer

Dim IY As Integer



Dim IMG As Long



IX = 64

IY = 16



IMG = _NewImage(IX, IY, 32)

   Please Humor me and do a PRINT IY right before the NewImage !   
(If you doing other things that would make that output hard to read then do a _DEST CONSOLE before the print ! )

[Unseen Machine]

If your calling the creation from within a Sub and the variable iy isnt shared then the sub cant access it.

So i.e 

DIM Shared AS INTEGER Iy

Would probably fix it 

Though without your full code this is just a guess...

Unseen

[ahenry3068]

If your calling the creation from within a Sub and the variable iy isnt shared then the sub cant access it.

So i.e 

DIM Shared AS INTEGER Iy

Would probably fix it 

Though without your full code this is just a guess...

Unseen

     I also suspect this, and did ask if the variable was in scope.   He says everything is declared in the same sub ?? 
There has to be an incorrect value somewhere which is why I asked him to print out the value right before his call to _NewImage !

[bplus]

Works fine for me _NewImage with variables in a sub:

Code: (Select All)

Option _Explicit

Screen _NewImage(800, 600, 32): _ScreenMove 280, 60

Dim I

For I = 1 To 100

    Line (Rnd * _Width, Rnd * _Height)-(Rnd * _Width, Rnd * _Height), _RGB32(Rnd * 255), BF

Next

Sleep

testNewImage





Sub testNewImage

    Dim SCR&, W, H, SQUARTER&

    SCR& = _ScreenImage

    W = _Width(SCR&) / 2

    H = _Height(SCR&) / 2



    SQUARTER& = _NewImage(W, H, 32)



    _PutImage , SCR&, SQUARTER&, (0, 0)-(W - 1, H - 1)

    Cls

    _PutImage , SQUARTER&, 0

    Print SCR&, W, H, SQUARTER&

End Sub

[Unseen Machine]

If @BPlus says it works then (as far as im concerned) IT WORKS! I've grown enough now (maturity!) to accept i dont know everything!

If you guys dont figure it out then call upon the gods (Steve, Pete, dBox, Petr) and they will help you!

john