Posts: 1,002
Threads: 50
Joined: May 2022
Reputation:
27
Can one also integrate the declaration of a library into a function?
The reason for the question is that I wrote a small program that allows one to use the tenary operator from C. If you could put the whole thing into a function, it might be useful for Basic. Maybe.
The Basic-Program:
Code: (Select All)
'Aufruf des tenaeren Operators in C - 30. Okt. 2023
Option _Explicit
'In QB64 mit "Declare Library" wie angegeben
Declare Library "D:\Lab\QuickBasic64\Extern-nicht-Basic\C-Aufruf\tenaerOp"
Function tenaerOp& (ByVal N As Long, Byval X As Long)
End Declare
Dim As Long N, X
X = 77
Locate 3, 3
Input "Zahl: ", N
Locate 5, 3
Print Using "Ausgabe: ###"; tenaerOp&(N&, X&)
End
The C part:
Code: (Select All) //TenaerenOperator von Basic aufrufen - 30. Okt. 2023
#include <stdio.h>
#include <stdlib.h>
long tenaerOp(long eingabe, long x)
{
long ausgabe;
ausgabe = x > eingabe ? 100 : 200;
return(ausgabe);
}
Posts: 303
Threads: 10
Joined: Apr 2022
Reputation:
44
Could you clarify what you're trying to achieve? You don't need C to write that function, the ternary operator is the same as just using an `if` for your usage:
Code: (Select All)
Function tenaerOp&(e As long, x As Long)
If x > e Then
tenaerOp& = 100
else
tenaerOp& = 200
End If
End Function
Unfortunately if you want a "real" ternary operator you can't implement that as a function. The ternary operator is only supposed to evaluate one of the true or false paths, not both, but there's no way to achieve that with a function call.
Posts: 3,973
Threads: 177
Joined: Apr 2022
Reputation:
219
10-30-2023, 11:08 PM
(This post was last modified: 10-30-2023, 11:16 PM by bplus.)
Code: (Select All) Print Iff$(_Width > _Height, "Landscape View", "Portrait View")
x = 150: e = 200
Print Iff$(x > e, "100", "200")
Function Iff$ (Bool&, true$, false$)
If Bool& <> 0 Then Iff$ = true$ Else Iff$ = false$
End Function
b = b + ...
Posts: 1,002
Threads: 50
Joined: May 2022
Reputation:
27
I know about "If", but in C, Java etc. the tenary operator is there not for fun.
Again: Can something like this be implemented in a function in QB64?
Posts: 303
Threads: 10
Joined: Apr 2022
Reputation:
44
(10-30-2023, 11:50 PM)Kernelpanic Wrote: Again: Can something like this be implemented in a function in QB64? Not in the way it behaves in languages like C and Java, it would have to be built into the language to work properly. Ex. In C and Java you can do stuff like this:
Code: (Select All) x = (a != 0)? 20 / a: 0; // Checks that a is not zero before dividing by it
There's no way to implement that correctly with a function. The `20 / a` in the ternary operator is only supposed to be evaluated if `a != 0` is true, but with functions all the arguments are evaluated before the function is called.
Posts: 3,973
Threads: 177
Joined: Apr 2022
Reputation:
219
Code: (Select All) For a = -1 To 1
x = Val(Iff$(a <> 0, _Trim$(Str$(20 / a)), "0"))
Print x
Next
Function Iff$ (Bool&, true$, false$)
If Bool& <> 0 Then Iff$ = true$ Else Iff$ = false$
End Function
b = b + ...
Posts: 303
Threads: 10
Joined: Apr 2022
Reputation:
44
(10-31-2023, 01:37 AM)bplus Wrote: Code: (Select All) For a = -1 To 1
x = Val(Iff$(a <> 0, _Trim$(Str$(20 / a)), "0"))
Print x
Next
Function Iff$ (Bool&, true$, false$)
If Bool& <> 0 Then Iff$ = true$ Else Iff$ = false$
End Function
Try it again, but skip the floating point math (where division by zero is technically allowed). Do `20 \ a` and the program always explodes, since it gets evaluated before calling the `Iff$()` function.
Posts: 3,973
Threads: 177
Joined: Apr 2022
Reputation:
219
10-31-2023, 02:02 AM
Got it! Thanks for the good example.
b = b + ...
Posts: 1,002
Threads: 50
Joined: May 2022
Reputation:
27
(10-31-2023, 01:13 AM)DSMan195276 Wrote: (10-30-2023, 11:50 PM)Kernelpanic Wrote: Again: Can something like this be implemented in a function in QB64? Not in the way it behaves in languages like C and Java, it would have to be built into the language to work properly. Ex. In C and Java you can do stuff like this:
Code: (Select All) x = (a != 0)? 20 / a: 0; // Checks that a is not zero before dividing by it
There's no way to implement that correctly with a function. The `20 / a` in the ternary operator is only supposed to be evaluated if `a != 0` is true, but with functions all the arguments are evaluated before the function is called. Yes, that obviously does not work. How should such and similar variations be intercepted?
Gets kind of complicated.
Code: (Select All)
'Tenaerer Operator , Problem in Funktion - 31. okt 2023
'x = (a != 0)? 20 / a: 0; // Checks that a is not zero before dividing by it
Option _Explicit
Declare Function tenaererOperator(a As Double, b As Double) As Doeble
Dim As Double a, b, x
Locate 3, 3
Input "Zahl a: ", a
Locate 4, 3
Input "Zahl b: ", b
If a <> 0 Then
x = b / a
Else
x = 0
End If
Locate 7, 3
Print Using "b / a = ##.####"; x
Locate 9, 3
If tenaererOperator(a, b) = -1 Then
Print "Keine negativen Werte!"
ElseIf tenaererOperator(a, b) = -2 Then
Print "Division durch Null!"
Else
Print Using "x = ###.####"; tenaererOperator(a, b)
End If
End
Function tenaererOperator (a As Double, b As Double)
Dim As Double x
If a <> 0 And Sgn(a) = 1 And Sgn(b) = 1 Then
x = b / a
ElseIf a <> 0 And Sgn(a) = -1 Then
x = -1
ElseIf a <> 0 And b = 0 Then
x = -2
Else
x = 0
End If
tenaererOperator = x
End Function
|